(2y+11)-(3y^2+2y-1)=

Solution for (2y+11)-(3y^2+2y-1)= equation:

Simplifying
(2y + 11) + -1(3y2 + 2y + -1) = 0

Reorder the terms:
(11 + 2y) + -1(3y2 + 2y + -1) = 0

Remove parenthesis around (11 + 2y)
11 + 2y + -1(3y2 + 2y + -1) = 0

Reorder the terms:
11 + 2y + -1(-1 + 2y + 3y2) = 0
11 + 2y + (-1 * -1 + 2y * -1 + 3y2 * -1) = 0
11 + 2y + (1 + -2y + -3y2) = 0

Reorder the terms:
11 + 1 + 2y + -2y + -3y2 = 0

Combine like terms: 11 + 1 = 12
12 + 2y + -2y + -3y2 = 0

Combine like terms: 2y + -2y = 0
12 + 0 + -3y2 = 0
12 + -3y2 = 0

Solving
12 + -3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -3y2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3y2 = 0 + -12
-3y2 = 0 + -12

Combine like terms: 0 + -12 = -12
-3y2 = -12

Divide each side by '-3'.
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}